My theory on Math

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I doubt you upset anyone Dragonrider.

As to your problems I'll give em a go real quick before I go for a run but I warn you it's been years.

You want to isolate the variable for each of em so you've got:

4(x-5) = 7x-9 rules of Algebra say multiply x through giving:

4x -20 = 7x - 9 then I would take that -20 and add the opposite on both sides of the equation so you'd get:

4x = 7x-9 +20 then you do the same thing with the 7x by subtracting 7x from each side so:

-3x= 11 then you just divide each side by -3 and end up with x = -11/3

Same thing with the other problem. Multiply 1/5 through then isolate 't' by getting the numbers without the variables on the same side and the numbers with the variables on the same side and then dividing. The only difference is you end up having two fractions on both sides I believe:

47/5 = (29/5)t so you'll divide 47/5 by 29/5 which is just to say you multiply 47/5 by 5/29 and get:

47/29 = t.

I haven't checked the answers but am pretty confident they're right. someone else may I have answered in the time it's taking me to do this but I'm not sure this method will be all that much help but hope so. My advice, just keep doing it over and over and eventually something will click and then you'll be able to do them all even years later. good luck

 

For simple algebra you have one equation with one unknown. Basically, to solve for any number of unknowns, you need the same number of different equations describing your unknowns.

In your case Dragonrider, the problem is very elementary:

step one - expand your equations to like terms: 4x-20=7x-9

step two - organize your equation by moving the variable x to one side and the numerals to the other. For instance what would happen if we subtracted 4x from the right side of the equation? For the equation to remain equal we would have to subtract 4x from both sides as follows: 4x-20-4x=7x-9-4x
leaving us with -20=3x-9,
now if we add 9 to both sides we have -20+9=3x-9+9
solving for this we end up with -11=3x
now it's a simple matter of dividing both sides of the equation by 3 : -11/3=3x/3
leaving -3 2/3 = x

There! it's easy. For equations like this with one variable just remember that anything you do to one side of the equation must also be done to the opposite side for the equation to remain equal. Now follow these same steps for your next example.

 

Just imagine you have a date in the city and need money.

THIS IS STEP ONE)
First tie out the mess with your "Ex"(expand the bracket)
SECOND)
You need to get all your "ex"s to the one side and all the money (numbers) to the other. (you dont want to waste money on your "ex"s
THIRD)
Give in to women. Let them all have a share of your money. (devide by the number of women "Ex"s)

Here is how it goes with your second

equation: 1/5(x+7)= 6x-8
STEP ONE (TIE OUT THE MESS)
1/5x + 1/5*7= 6x-8
STEP TWO (GET YOUR MONEY AND EXes SEPERATED)
1/5x -6x = -8 - 1/5*7
STEP THREE (LET THE WOMEN HAVE A SHARE)
so how many women are there? 1/5x -6x = -5.80x
And how much money? -8 - 1/5*7 = -9.40
So the equation looks like this:
-5.80x= -9.40
THEN DIVIDE THE MONEY BETWEEN YOUR WOMEN. (divide by -5.80)
x= -9.40/-5.80

Thats it. Good luck

And who said Math couldn't be used in real life

[This message has been edited by Nobleman (edited October 12, 2001).]

 

Thank you all! Some how reading your posts turned something on. I can do it now with little problem. thank you all so much!

 

theoretically speaking thalantyr, you could argue yourself out of many of the stuff they teach at school/college and end up uneducated

 

I'll get Thal his point. I had Math for 5 years. Now I work and I never have used anything I learned at Math.. some things are sooo useless to learn.

 

Invoker---- you are probably right about that.

 

So How did it go my friend? Did you finish the test? If not we give you a 24 hour practice sevice here at SP

 

Ok well i took my test and equation last night for awile. Well lets just say i didn't get a A. I thank you all for your help even though I didn't do well. It shows that at SP is really a helpful place. Thanks again.

 

Minsc needs no math! Minsc only knows sword plus evil equals no more evil!

 

Minsc you rule to bad my nickname is not boo
=( I would have had alot more fun here.

 

Minsc thanks Thalantyr for his kind words.

*Boo* Eeeeep eeep eeeep.

Yes, Boo. Minsc thinks there can be only one Boo, but he has room for one Thal in fighting evil-doers.

 

hey thal.. this Minsc posting wouldn't be your alter ego now would it

 

to tell you the truth it really is not me.